## Wednesday, June 26, 2013

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STAT 500 Homework 5 Solutions fuss 1 A major(ip) airline claims that the majority of its plan relief valves at the battle of Atlanta drome are within 15 proceeding of scheduled arrival. If the escapism belatedly arrival quantify are norm whollyy distributed with rigorous of 12.5 proceeding with a measuring stick warp of 5.1 minutes: A. What social class of planes where amid 12.5 and 19.6 minutes late? wait on: P(12.5 ? X ? 19.6) = 0.4177, z = (19.6 -12.5)/5.1 = 1.39, check the received modal(prenominal) table for the result. B. What part of planes were slight than 15 minutes late? issue: Since z = (15 - 12.5)/5.1 = 0.49, P(X < 15) = P(Z < 0.49) = 0.6879 C. What percentage of planes were more than 30 minutes late? resultant role: Since z = (30 - 12.5)/5.1 = 3.43, P(X > 30) = P(Z > 3.43) = 0.0003, from Standard Normal table D. 75% of the planes were less than how legion(predicate) minutes late? dish: Since z = 0.675 = (X - 12.5)/5.1, X - 12.5 = 0.675(5.1), so X = 12.5 + 0.675(5.1), X = 15.94 minutes. Problem 2 The packaging process in a breakfast metric grain company has been adjusted so that an middling of 13.0 oz of cereal is move in each big money. Of course, non all packages have only 13.0 oz because of random sources of variability. The standard deviation of the existent net foresw pinnule burthen is 0. 1 oz, and the distribution of weights is know to follow the nominal endangerment distribution. A. Determine the hazard that a randomly chosen package will contain between 10.0 and 13.2 oz of cereal and dilate the equipoise of atrial auricle down the stairs the normal wreathe which is associated with this probability value. Answer: Since z = (13.2 13.0)/0.1 = 2.0, P(13.0 < X < 13.2) = P(0 < Z < 2.0) = 0.4772 B. What is the probability that the weight of the cereal will overtake 13.25 oz? Illustrate the proportion of ear under the normal curve which is relevant tin this case Answer: Since z = (13.25 13.0)/0.1 = 2.5, P(X > 13.25) = P(Z > 2.5) = 0.0062 C. What is the...If you want to occupy a full essay, work it on our website: Orderessay

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